模板类专业化和朋友类[关闭](Template class specialization and friend classes [closed])
我遇到以下情况：
template<typename T, int N> class Foo { }; // specialization for 0 template<typename T> class Foo<0> { friend class Foo<T, 1>; };也就是说，我需要Foo<T, 1>是Foo<T, 0>朋友，但我有编译错误。 这可能吗？
I am in the following situation:
template<typename T, int N> class Foo { }; // specialization for 0 template<typename T> class Foo<0> { friend class Foo<T, 1>; };That is, I need that Foo<T, 1> is friend of Foo<T, 0>, but I have a compiler error. Is this possible?
最满意答案
你的专业化有一个错字：
template<typename T> class Foo<T, 0> { // ^^^ <= add this friend class Foo<T, 1>; };You have a typo in your specialization:
template<typename T> class Foo<T, 0> { // ^^^ <= add this friend class Foo<T, 1>; };模板类专业化和朋友类[关闭](Template class specialization and friend classes [closed])我遇到以下情况：
template<typename T, int N> class Foo { }; // specialization for 0 template<typename T> class Foo<0> { friend class Foo<T, 1>; };也就是说，我需要Foo<T, 1>是Foo<T, 0>朋友，但我有编译错误。 这可能吗？
I am in the following situation:
template<typename T, int N> class Foo { }; // specialization for 0 template<typename T> class Foo<0> { friend class Foo<T, 1>; };That is, I need that Foo<T, 1> is friend of Foo<T, 0>, but I have a compiler error. Is this possible?
最满意答案
你的专业化有一个错字：
template<typename T> class Foo<T, 0> { // ^^^ <= add this friend class Foo<T, 1>; };You have a typo in your specialization:
template<typename T> class Foo<T, 0> { // ^^^ <= add this friend class Foo<T, 1>; };
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