^ Swift中的运算符(^ operator in Swift)

通过可哈希协议来查看，并使矩阵位置结构符合：

struct MatrixLocation: Hashable { let row: Int let col: Int var hashValue: Int { return row.hashValue ^ col.hashValue } }

散列值具有^运算符。

什么是Swift中的^运算符。

提前对这个问题表示歉意。

Looking through the hashable protocol, and to make a matrix location struct to conform:

struct MatrixLocation: Hashable { let row: Int let col: Int var hashValue: Int { return row.hashValue ^ col.hashValue } }

The hash value has the ^ operator.

What is the ^ operator in Swift?

最满意答案

^是Swift中的XOR运算符。 基本上它比较两个操作数的位，并且如果两个输入位之一是1 ，而另一个是0 ，则它将每个位设置结果的相应位为1 。 如果两位均为1或两位均为0 ，则将结果中的位设置为0 。

所以如果你有0x49 ^ 0x13 ，那将是01001001 XOR 00010011，它会出现在01011010或0x5a 。

^ is the XOR operator in Swift. Basically it compares the bits of the two operands, and for each bit, it sets the corresponding bit of the result to 1 if one of the two input bits is 1, but the other is 0. If both bits are 1 or both bits are 0, it sets the bit in the result to 0.

So if you have 0x49 ^ 0x13, that would be 01001001 XOR 00010011, which would come out to 01011010, or 0x5a.

^ Swift中的运算符(^ operator in Swift)

通过可哈希协议来查看，并使矩阵位置结构符合：

struct MatrixLocation: Hashable { let row: Int let col: Int var hashValue: Int { return row.hashValue ^ col.hashValue } }

散列值具有^运算符。

什么是Swift中的^运算符。

提前对这个问题表示歉意。

Looking through the hashable protocol, and to make a matrix location struct to conform:

struct MatrixLocation: Hashable { let row: Int let col: Int var hashValue: Int { return row.hashValue ^ col.hashValue } }

The hash value has the ^ operator.

What is the ^ operator in Swift?

最满意答案

^是Swift中的XOR运算符。 基本上它比较两个操作数的位，并且如果两个输入位之一是1 ，而另一个是0 ，则它将每个位设置结果的相应位为1 。 如果两位均为1或两位均为0 ，则将结果中的位设置为0 。

所以如果你有0x49 ^ 0x13 ，那将是01001001 XOR 00010011，它会出现在01011010或0x5a 。

^ is the XOR operator in Swift. Basically it compares the bits of the two operands, and for each bit, it sets the corresponding bit of the result to 1 if one of the two input bits is 1, but the other is 0. If both bits are 1 or both bits are 0, it sets the bit in the result to 0.

So if you have 0x49 ^ 0x13, that would be 01001001 XOR 00010011, which would come out to 01011010, or 0x5a.