使用随机对生成单元格而不重复(Generate cell with random pairs without repetitions)

如何生成一系列随机对而不重复对？ 以下代码已生成对，但不避免重复：

for k=1:8 Comb=[randi([-15,15]) ; randi([-15,15])]; T{1,k}=Comb; end

跑步时我得到了：

T= [-3;10] [5;2] [1;-5] [10;9] [-4;-9] [-5;-9] [3;1] [-3;10]

重复对[-3,10]，这是不可能发生的。

PS：条目可以是正面的也可以是负面的。

这有什么内置功能吗？ 任何解决这个问题的消化方法？

How to generate a sequence of random pairs without repeating pairs? The following code already generates the pairs, but does not avoid repetitions:

for k=1:8 Comb=[randi([-15,15]) ; randi([-15,15])]; T{1,k}=Comb; end

When running I got:

T= [-3;10] [5;2] [1;-5] [10;9] [-4;-9] [-5;-9] [3;1] [-3;10]

The pair [-3,10] is repeated, which cannot happen.

PS : The entries can be positive or negative.

Is there any built in function for this? Any sugestion to solve this?

最满意答案

如果您有统计工具箱，则可以使用randsample从1到31^2 （其中31是总体大小）中抽取8数字，而无需替换，然后将每个获得的数字“解包”到一对的两个组件中：

s = -15:15; % population M = 8; % desired number of samples N = numel(s); % population size y = randsample(N^2, M); % sample without replacement result = s([ceil(y/N) mod(y-1, N)+1]); % unpack pair and index into population

示例运行：

result = 14 1 -5 7 13 -8 15 4 -6 -7 -6 15 2 3 9 6

If you have the Statistics Toolbox, you can use randsample to sample 8 numbers from 1 to 31^2 (where 31 is the population size), without replacement, and then "unpack" each obtained number into the two components of a pair:

s = -15:15; % population M = 8; % desired number of samples N = numel(s); % population size y = randsample(N^2, M); % sample without replacement result = s([ceil(y/N) mod(y-1, N)+1]); % unpack pair and index into population

Example run:

result = 14 1 -5 7 13 -8 15 4 -6 -7 -6 15 2 3 9 6使用随机对生成单元格而不重复(Generate cell with random pairs without repetitions)

如何生成一系列随机对而不重复对？ 以下代码已生成对，但不避免重复：

for k=1:8 Comb=[randi([-15,15]) ; randi([-15,15])]; T{1,k}=Comb; end

跑步时我得到了：

T= [-3;10] [5;2] [1;-5] [10;9] [-4;-9] [-5;-9] [3;1] [-3;10]

重复对[-3,10]，这是不可能发生的。

PS：条目可以是正面的也可以是负面的。

这有什么内置功能吗？ 任何解决这个问题的消化方法？

How to generate a sequence of random pairs without repeating pairs? The following code already generates the pairs, but does not avoid repetitions:

for k=1:8 Comb=[randi([-15,15]) ; randi([-15,15])]; T{1,k}=Comb; end

When running I got:

T= [-3;10] [5;2] [1;-5] [10;9] [-4;-9] [-5;-9] [3;1] [-3;10]

The pair [-3,10] is repeated, which cannot happen.

PS : The entries can be positive or negative.

Is there any built in function for this? Any sugestion to solve this?

最满意答案

如果您有统计工具箱，则可以使用randsample从1到31^2 （其中31是总体大小）中抽取8数字，而无需替换，然后将每个获得的数字“解包”到一对的两个组件中：

s = -15:15; % population M = 8; % desired number of samples N = numel(s); % population size y = randsample(N^2, M); % sample without replacement result = s([ceil(y/N) mod(y-1, N)+1]); % unpack pair and index into population

示例运行：

result = 14 1 -5 7 13 -8 15 4 -6 -7 -6 15 2 3 9 6

If you have the Statistics Toolbox, you can use randsample to sample 8 numbers from 1 to 31^2 (where 31 is the population size), without replacement, and then "unpack" each obtained number into the two components of a pair:

s = -15:15; % population M = 8; % desired number of samples N = numel(s); % population size y = randsample(N^2, M); % sample without replacement result = s([ceil(y/N) mod(y-1, N)+1]); % unpack pair and index into population

Example run:

result = 14 1 -5 7 13 -8 15 4 -6 -7 -6 15 2 3 9 6